(x+3)(x+1)=4x-7

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Solution for (x+3)(x+1)=4x-7 equation: 



(x+3)(x+1)=4x-7

We move all terms to the left:

(x+3)(x+1)-(4x-7)=0

We get rid of parentheses

(x+3)(x+1)-4x+7=0

We multiply parentheses ..

(+x^2+x+3x+3)-4x+7=0

We get rid of parentheses

x^2+x+3x-4x+3+7=0

We add all the numbers together, and all the variables

x^2+10=0

a = 1; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·1·10
Δ = -40
Delta is less than zero, so there is no solution for the equation

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