(x+3)(4x-6)=0

Solution for (x+3)(4x-6)=0 equation:

(x+3)(4x-6)=0

We multiply parentheses ..

(+4x^2-6x+12x-18)=0

We get rid of parentheses

4x^2-6x+12x-18=0

We add all the numbers together, and all the variables

4x^2+6x-18=0

a = 4; b = 6; c = -18;
Δ = b2-4ac
Δ = 62-4·4·(-18)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*4}=\frac{-24}{8}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*4}=\frac{12}{8}
=1+1/2
$