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(x+3)(4+x)=5x
We move all terms to the left:
(x+3)(4+x)-(5x)=0
We add all the numbers together, and all the variables
(x+3)(x+4)-5x=0
We add all the numbers together, and all the variables
-5x+(x+3)(x+4)=0
We multiply parentheses ..
(+x^2+4x+3x+12)-5x=0
We get rid of parentheses
x^2+4x+3x-5x+12=0
We add all the numbers together, and all the variables
x^2+2x+12=0
a = 1; b = 2; c = +12;
Δ = b2-4ac
Δ = 22-4·1·12
Δ = -44
Delta is less than zero, so there is no solution for the equation
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