(x+2y+1)dx-(2x-3)dy=0

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Solution for (x+2y+1)dx-(2x-3)dy=0 equation: 


Simplifying
(x + 2y + 1) * dx + -1(2x + -3) * dy = 0

Reorder the terms:
(1 + x + 2y) * dx + -1(2x + -3) * dy = 0

Reorder the terms for easier multiplication:
dx(1 + x + 2y) + -1(2x + -3) * dy = 0
(1 * dx + x * dx + 2y * dx) + -1(2x + -3) * dy = 0

Reorder the terms:
(1dx + 2dxy + dx2) + -1(2x + -3) * dy = 0
(1dx + 2dxy + dx2) + -1(2x + -3) * dy = 0

Reorder the terms:
1dx + 2dxy + dx2 + -1(-3 + 2x) * dy = 0

Reorder the terms for easier multiplication:
1dx + 2dxy + dx2 + -1dy(-3 + 2x) = 0
1dx + 2dxy + dx2 + (-3 * -1dy + 2x * -1dy) = 0

Reorder the terms:
1dx + 2dxy + dx2 + (-2dxy + 3dy) = 0
1dx + 2dxy + dx2 + (-2dxy + 3dy) = 0

Reorder the terms:
1dx + 2dxy + -2dxy + dx2 + 3dy = 0

Combine like terms: 2dxy + -2dxy = 0
1dx + 0 + dx2 + 3dy = 0
1dx + dx2 + 3dy = 0

Solving
1dx + dx2 + 3dy = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), 'd'.
d(x + x2 + 3y) = 0


Subproblem 1
Set the factor 'd' equal to zero and attempt to solve:

Simplifying
d = 0

Solving
d = 0

Move all terms containing d to the left, all other terms to the right.

Simplifying
d = 0

Subproblem 2
Set the factor '(x + x2 + 3y)' equal to zero and attempt to solve:

Simplifying
x + x2 + 3y = 0

Solving
x + x2 + 3y = 0

Move all terms containing d to the left, all other terms to the right.

Add '-1x' to each side of the equation.
x + x2 + -1x + 3y = 0 + -1x

Reorder the terms:
x + -1x + x2 + 3y = 0 + -1x

Combine like terms: x + -1x = 0
0 + x2 + 3y = 0 + -1x
x2 + 3y = 0 + -1x
Remove the zero:
x2 + 3y = -1x

Add '-1x2' to each side of the equation.
x2 + -1x2 + 3y = -1x + -1x2

Combine like terms: x2 + -1x2 = 0
0 + 3y = -1x + -1x2
3y = -1x + -1x2

Add '-3y' to each side of the equation.
3y + -3y = -1x + -1x2 + -3y

Combine like terms: 3y + -3y = 0
0 = -1x + -1x2 + -3y

Simplifying
0 = -1x + -1x2 + -3y

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
d = {0}

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