(x+2i)(x-2i)=0

Solution for (x+2i)(x-2i)=0 equation:

Simplifying
(x + 2i)(x + -2i) = 0

Reorder the terms:
(2i + x)(x + -2i) = 0

Reorder the terms:
(2i + x)(-2i + x) = 0

Multiply (2i + x) * (-2i + x)
(2i * (-2i + x) + x(-2i + x)) = 0
((-2i * 2i + x * 2i) + x(-2i + x)) = 0

Reorder the terms:
((2ix + -4i2) + x(-2i + x)) = 0
((2ix + -4i2) + x(-2i + x)) = 0
(2ix + -4i2 + (-2i * x + x * x)) = 0
(2ix + -4i2 + (-2ix + x2)) = 0

Reorder the terms:
(2ix + -2ix + -4i2 + x2) = 0

Combine like terms: 2ix + -2ix = 0
(0 + -4i2 + x2) = 0
(-4i2 + x2) = 0

Solving
-4i2 + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
-4i2 + x2 + -1x2 = 0 + -1x2

Combine like terms: x2 + -1x2 = 0
-4i2 + 0 = 0 + -1x2
-4i2 = 0 + -1x2
Remove the zero:
-4i2 = -1x2

Divide each side by '-4'.
i2 = 0.25x2

Simplifying
i2 = 0.25x2

Take the square root of each side:
i = {-0.5x, 0.5x}