(x+26)-10=(27+x)-3x+47

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Solution for (x+26)-10=(27+x)-3x+47 equation: 



(x+26)-10=(27+x)-3x+47

We move all terms to the left:

(x+26)-10-((27+x)-3x+47)=0

We add all the numbers together, and all the variables

(x+26)-((x+27)-3x+47)-10=0

We get rid of parentheses

x-((x+27)-3x+47)+26-10=0



We calculate terms in parentheses: -((x+27)-3x+47), so:

(x+27)-3x+47

We add all the numbers together, and all the variables

-3x+(x+27)+47

We get rid of parentheses

-3x+x+27+47

We add all the numbers together, and all the variables

-2x+74

Back to the equation:

-(-2x+74)



We add all the numbers together, and all the variables

x-(-2x+74)+16=0

We get rid of parentheses

x+2x-74+16=0

We add all the numbers together, and all the variables

3x-58=0

We move all terms containing x to the left, all other terms to the right

3x=58

x=58/3

x=19+1/3

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