(x+2)x=483

Solution for (x+2)x=483 equation:

(x+2)x=483

We move all terms to the left:

(x+2)x-(483)=0

We multiply parentheses

x^2+2x-483=0

a = 1; b = 2; c = -483;
Δ = b2-4ac
Δ = 22-4·1·(-483)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-44}{2*1}=\frac{-46}{2}
=-23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+44}{2*1}=\frac{42}{2}
=21
$