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(x+2)2=x2+6
We move all terms to the left:
(x+2)2-(x2+6)=0
We add all the numbers together, and all the variables
-(+x^2+6)+(x+2)2=0
We multiply parentheses
-(+x^2+6)+2x+4=0
We get rid of parentheses
-x^2+2x-6+4=0
We add all the numbers together, and all the variables
-1x^2+2x-2=0
a = -1; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·(-1)·(-2)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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