(x+2)/x=(x-1)/(x+3)

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Solution for (x+2)/x=(x-1)/(x+3) equation: 



(x+2)/x=(x-1)/(x+3)

We move all terms to the left:

(x+2)/x-((x-1)/(x+3))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+3))!=0

x∈R



We calculate fractions


((x+2)*(x+3)))/4x^2+(-((x-1)*x)/4x^2=0

We calculate fractions


(((x+2)*(x+3)))*4x^2)/(4x^2+(*4x^2)+(-((x-1)*x)*4x^2)/(4x^2+(*4x^2)=0



We calculate terms in parentheses: +(-((x-1)*x)*4x^2)/(4x^2+(*4x^2), so:

-((x-1)*x)*4x^2)/(4x^2+(*4x^2

We multiply all the terms by the denominator


-((x-1)*x)*4x^2)+((*4x^2)*(4x^2

Back to the equation:

+(-((x-1)*x)*4x^2)+((*4x^2)*(4x^2)



We get rid of parentheses

(((x+2)*(x+3)))*4x^2)/(4x^2+*4x^2+(-((x-1)*x)*4x^2)+((*4x^2)*4x^2=0

We multiply all the terms by the denominator


(((x+2)*(x+3)))*4x^2)+(*4x^2)*(4x^2+((-((x-1)*x)*4x^2))*(4x^2+(((*4x^2)*4x^2)*(4x^2=0

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