(x+2)/6=(x-1)/2

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Solution for (x+2)/6=(x-1)/2 equation: 



(x+2)/6=(x-1)/2

We move all terms to the left:

(x+2)/6-((x-1)/2)=0

We calculate fractions


x/()+(-((x-1)*6)/()=0



We calculate terms in parentheses: +(-((x-1)*6)/(), so:

-((x-1)*6)/(

We multiply all the terms by the denominator


-((x-1)*6)



We calculate terms in parentheses: -((x-1)*6), so:

(x-1)*6

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

-6x+6

Back to the equation:

+(-6x+6)



We get rid of parentheses

x/()-6x+6=0

We multiply all the terms by the denominator


x-6x*()+6*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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