(x+2)/5=3-(x+5)/2

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Solution for (x+2)/5=3-(x+5)/2 equation: 



(x+2)/5=3-(x+5)/2

We move all terms to the left:

(x+2)/5-(3-(x+5)/2)=0

We calculate fractions


x/()+(-(3-(x+5)*5)/()=0



We calculate terms in parentheses: +(-(3-(x+5)*5)/(), so:

-(3-(x+5)*5)/(

We multiply all the terms by the denominator


-(3-(x+5)*5)



We calculate terms in parentheses: -(3-(x+5)*5), so:

3-(x+5)*5

determiningTheFunctionDomain
-(x+5)*5+3

We multiply parentheses

-5x-25+3

We add all the numbers together, and all the variables

-5x-22

Back to the equation:

-(-5x-22)



We get rid of parentheses

5x+22

Back to the equation:

+(5x+22)



We get rid of parentheses

x/()+5x+22=0

We multiply all the terms by the denominator


x+5x*()+22*()=0

We add all the numbers together, and all the variables

x+5x*()=0

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