(x+2)/(x-1)+1=(3)/(x-1)

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Solution for (x+2)/(x-1)+1=(3)/(x-1) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(x+2)/(x-1)+1 = 3/(x-1) // - 3/(x-1)

(x+2)/(x-1)-(3/(x-1))+1 = 0

(x+2)/(x-1)-3*(x-1)^-1+1 = 0

(x+2)/(x-1)-3/(x-1)+1 = 0

(x+2)/(x-1)-3/(x-1)+(1*(x-1))/(x-1) = 0

1*(x-1)+x-3+2 = 0

x+x-1-1 = 0

2*x-2 = 0

(2*x-2)/(x-1) = 0

(2*x-2)/(x-1) = 0 // * x-1

2*x-2 = 0

2*x-2 = 0 // + 2

2*x = 2 // : 2

x = 2/2

x = 1

x in { 1} 

x belongs to the empty set

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