(x+2)/(x-1)+(x+1)/(3-x)=0

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Solution for (x+2)/(x-1)+(x+1)/(3-x)=0 equation: 



(x+2)/(x-1)+(x+1)/(3-x)=0



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R





Domain of the equation: (3-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-3

x!=-3/-1

x!=+3

x∈R



We add all the numbers together, and all the variables

(x+2)/(x-1)+(x+1)/(-1x+3)=0

We calculate fractions


((x+2)*(-1x+3))/((x-1)*(-1x+3))+((x+1)*(x-1))/((x-1)*(-1x+3))=0



We calculate terms in parentheses: +((x+2)*(-1x+3))/((x-1)*(-1x+3)), so:

(x+2)*(-1x+3))/((x-1)*(-1x+3)

We multiply all the terms by the denominator


(x+2)*(-1x+3))

Back to the equation:

+((x+2)*(-1x+3)))





We calculate terms in parentheses: +((x+1)*(x-1))/((x-1)*(-1x+3)), so:

(x+1)*(x-1))/((x-1)*(-1x+3)

We multiply all the terms by the denominator


(x+1)*(x-1))

Back to the equation:

+((x+1)*(x-1)))





We calculate terms in parentheses: +((x+2)*(-1x+3)))+((x+1)*(x-1))), so:

(x+2)*(-1x+3)))+((x+1)*(x-1))

We add all the numbers together, and all the variables

(x+2)*(-1x+3)))+((x+1)*(x

Back to the equation:

+((x+2)*(-1x+3)))+((x+1)*(x)

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