(x+2)/(2x+1)=1/3

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Solution for (x+2)/(2x+1)=1/3 equation: 


D( x )

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

(x+2)/(2*x+1) = 1/3 // - 1/3

(x+2)/(2*x+1)-(1/3) = 0

(x+2)/(2*x+1)-1/3 = 0

(3*(x+2))/(3*(2*x+1))+(-1*(2*x+1))/(3*(2*x+1)) = 0

3*(x+2)-1*(2*x+1) = 0

x+5 = 0

(x+5)/(3*(2*x+1)) = 0

(x+5)/(3*(2*x+1)) = 0 // * 3*(2*x+1)

x+5 = 0

x+5 = 0 // - 5

x = -5

x = -5

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