(x+2)-(5-x)=5+(2-2x)

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Solution for (x+2)-(5-x)=5+(2-2x) equation: 



(x+2)-(5-x)=5+(2-2x)

We move all terms to the left:

(x+2)-(5-x)-(5+(2-2x))=0

We add all the numbers together, and all the variables

(x+2)-(-1x+5)-(5+(-2x+2))=0

We get rid of parentheses

x+1x-(5+(-2x+2))+2-5=0



We calculate terms in parentheses: -(5+(-2x+2)), so:

5+(-2x+2)

determiningTheFunctionDomain
(-2x+2)+5

We get rid of parentheses

-2x+2+5

We add all the numbers together, and all the variables

-2x+7

Back to the equation:

-(-2x+7)



We add all the numbers together, and all the variables

2x-(-2x+7)-3=0

We get rid of parentheses

2x+2x-7-3=0

We add all the numbers together, and all the variables

4x-10=0

We move all terms containing x to the left, all other terms to the right

4x=10

x=10/4

x=2+1/2

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