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(x+2)+(x+1)+2=x+(2x+1)
We move all terms to the left:
(x+2)+(x+1)+2-(x+(2x+1))=0
We get rid of parentheses
x+x-(x+(2x+1))+2+1+2=0
We calculate terms in parentheses: -(x+(2x+1)), so:We add all the numbers together, and all the variables
x+(2x+1)
We get rid of parentheses
x+2x+1
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
2x-(3x+1)+5=0
We get rid of parentheses
2x-3x-1+5=0
We add all the numbers together, and all the variables
-1x+4=0
We move all terms containing x to the left, all other terms to the right
-x=-4
x=-4/-1
x=+4
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