(x+2)+(2x+2)+(5x+2)=58

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Solution for (x+2)+(2x+2)+(5x+2)=58 equation: 



(x+2)+(2x+2)+(5x+2)=58

We move all terms to the left:

(x+2)+(2x+2)+(5x+2)-(58)=0

We get rid of parentheses

x+2x+5x+2+2+2-58=0

We add all the numbers together, and all the variables

8x-52=0

We move all terms containing x to the left, all other terms to the right

8x=52

x=52/8

x=6+1/2

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