(x+2)*(x-3)=x*(x-2)

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Solution for (x+2)*(x-3)=x*(x-2) equation: 



(x+2)(x-3)=x(x-2)

We move all terms to the left:

(x+2)(x-3)-(x(x-2))=0

We multiply parentheses ..

(+x^2-3x+2x-6)-(x(x-2))=0



We calculate terms in parentheses: -(x(x-2)), so:

x(x-2)

We multiply parentheses

x^2-2x

Back to the equation:

-(x^2-2x)



We get rid of parentheses

x^2-x^2-3x+2x+2x-6=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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