(x+2)*(x+4)*3=144

Solution for (x+2)*(x+4)*3=144 equation:

(x+2)(x+4)*3=144

We move all terms to the left:

(x+2)(x+4)*3-(144)=0

We multiply parentheses ..

(+x^2+4x+2x+8)*3-144=0

We multiply parentheses

3x^2+12x+6x+24-144=0

We add all the numbers together, and all the variables

3x^2+18x-120=0

a = 3; b = 18; c = -120;
Δ = b2-4ac
Δ = 182-4·3·(-120)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-42}{2*3}=\frac{-60}{6}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+42}{2*3}=\frac{24}{6}
=4
$