(x+2)*(3x-6)=0

Solution for (x+2)*(3x-6)=0 equation:

Simplifying
(x + 2)(3x + -6) = 0

Reorder the terms:
(2 + x)(3x + -6) = 0

Reorder the terms:
(2 + x)(-6 + 3x) = 0

Multiply (2 + x) * (-6 + 3x)
(2(-6 + 3x) + x(-6 + 3x)) = 0
((-6 * 2 + 3x * 2) + x(-6 + 3x)) = 0
((-12 + 6x) + x(-6 + 3x)) = 0
(-12 + 6x + (-6 * x + 3x * x)) = 0
(-12 + 6x + (-6x + 3x2)) = 0

Combine like terms: 6x + -6x = 0
(-12 + 0 + 3x2) = 0
(-12 + 3x2) = 0

Solving
-12 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 3x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 3x2 = 0 + 12
3x2 = 0 + 12

Combine like terms: 0 + 12 = 12
3x2 = 12

Divide each side by '3'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}