(x+2)*(2x-4)=(2x-1)*x

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Solution for (x+2)*(2x-4)=(2x-1)*x equation: 



(x+2)(2x-4)=(2x-1)*x

We move all terms to the left:

(x+2)(2x-4)-((2x-1)*x)=0

We multiply parentheses ..

(+2x^2-4x+4x-8)-((2x-1)*x)=0



We calculate terms in parentheses: -((2x-1)*x), so:

(2x-1)*x

We multiply parentheses

2x^2-1x

Back to the equation:

-(2x^2-1x)



We get rid of parentheses

2x^2-2x^2-4x+4x+1x-8=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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