(x+2)(x-4)(x-6)(x-8)=0

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Solution for (x+2)(x-4)(x-6)(x-8)=0 equation: 



(x+2)(x-4)(x-6)(x-8)=0

We multiply parentheses ..

(+x^2-4x+2x-8)(x-6)(x-8)=0

We multiply parentheses ..

(+x^2-4x+2x-8)(+x^2-8x-6x+48)=0

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