(x+2)(x-2)(x-1)=0

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Solution for (x+2)(x-2)(x-1)=0 equation: 


Simplifying
(x + 2)(x + -2)(x + -1) = 0

Reorder the terms:
(2 + x)(x + -2)(x + -1) = 0

Reorder the terms:
(2 + x)(-2 + x)(x + -1) = 0

Reorder the terms:
(2 + x)(-2 + x)(-1 + x) = 0

Multiply (2 + x) * (-2 + x)
(2(-2 + x) + x(-2 + x))(-1 + x) = 0
((-2 * 2 + x * 2) + x(-2 + x))(-1 + x) = 0
((-4 + 2x) + x(-2 + x))(-1 + x) = 0
(-4 + 2x + (-2 * x + x * x))(-1 + x) = 0
(-4 + 2x + (-2x + x2))(-1 + x) = 0

Combine like terms: 2x + -2x = 0
(-4 + 0 + x2)(-1 + x) = 0
(-4 + x2)(-1 + x) = 0

Multiply (-4 + x2) * (-1 + x)
(-4(-1 + x) + x2(-1 + x)) = 0
((-1 * -4 + x * -4) + x2(-1 + x)) = 0
((4 + -4x) + x2(-1 + x)) = 0
(4 + -4x + (-1 * x2 + x * x2)) = 0
(4 + -4x + (-1x2 + x3)) = 0
(4 + -4x + -1x2 + x3) = 0

Solving
4 + -4x + -1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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