(x+2)(x+5)=3(4x-3)+(5-x)

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Solution for (x+2)(x+5)=3(4x-3)+(5-x) equation: 



(x+2)(x+5)=3(4x-3)+(5-x)

We move all terms to the left:

(x+2)(x+5)-(3(4x-3)+(5-x))=0

We add all the numbers together, and all the variables

(x+2)(x+5)-(3(4x-3)+(-1x+5))=0

We multiply parentheses ..

(+x^2+5x+2x+10)-(3(4x-3)+(-1x+5))=0



We calculate terms in parentheses: -(3(4x-3)+(-1x+5)), so:

3(4x-3)+(-1x+5)

We multiply parentheses

12x+(-1x+5)-9

We get rid of parentheses

12x-1x+5-9

We add all the numbers together, and all the variables

11x-4

Back to the equation:

-(11x-4)



We get rid of parentheses

x^2+5x+2x-11x+10+4=0

We add all the numbers together, and all the variables

x^2-4x+14=0

a = 1; b = -4; c = +14;
Δ = b2-4ac
Δ = -42-4·1·14
Δ = -40
Delta is less than zero, so there is no solution for the equation

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