(x+2)(x+3)=(x=1)(x+50

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Solution for (x+2)(x+3)=(x=1)(x+50 equation: 



(x+2)(x+3)=(x=1)(x+50

We move all terms to the left:

(x+2)(x+3)-((x)=0

We multiply parentheses ..

(+x^2+3x+2x+6)-(x=0

We get rid of parentheses

x^2+3x+2x-(x+6=0

We add all the numbers together, and all the variables

x^2+5x-(x+6=0

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