(x+2)(x+2)-4(x+2)=12

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Solution for (x+2)(x+2)-4(x+2)=12 equation: 


Simplifying
(x + 2)(x + 2) + -4(x + 2) = 12

Reorder the terms:
(2 + x)(x + 2) + -4(x + 2) = 12

Reorder the terms:
(2 + x)(2 + x) + -4(x + 2) = 12

Multiply (2 + x) * (2 + x)
(2(2 + x) + x(2 + x)) + -4(x + 2) = 12
((2 * 2 + x * 2) + x(2 + x)) + -4(x + 2) = 12
((4 + 2x) + x(2 + x)) + -4(x + 2) = 12
(4 + 2x + (2 * x + x * x)) + -4(x + 2) = 12
(4 + 2x + (2x + x2)) + -4(x + 2) = 12

Combine like terms: 2x + 2x = 4x
(4 + 4x + x2) + -4(x + 2) = 12

Reorder the terms:
4 + 4x + x2 + -4(2 + x) = 12
4 + 4x + x2 + (2 * -4 + x * -4) = 12
4 + 4x + x2 + (-8 + -4x) = 12

Reorder the terms:
4 + -8 + 4x + -4x + x2 = 12

Combine like terms: 4 + -8 = -4
-4 + 4x + -4x + x2 = 12

Combine like terms: 4x + -4x = 0
-4 + 0 + x2 = 12
-4 + x2 = 12

Solving
-4 + x2 = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + x2 = 12 + 4

Combine like terms: -4 + 4 = 0
0 + x2 = 12 + 4
x2 = 12 + 4

Combine like terms: 12 + 4 = 16
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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