(x+2)(x+12)=0

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Solution for (x+2)(x+12)=0 equation:


Simplifying
(x + 2)(x + 12) = 0

Reorder the terms:
(2 + x)(x + 12) = 0

Reorder the terms:
(2 + x)(12 + x) = 0

Multiply (2 + x) * (12 + x)
(2(12 + x) + x(12 + x)) = 0
((12 * 2 + x * 2) + x(12 + x)) = 0
((24 + 2x) + x(12 + x)) = 0
(24 + 2x + (12 * x + x * x)) = 0
(24 + 2x + (12x + x2)) = 0

Combine like terms: 2x + 12x = 14x
(24 + 14x + x2) = 0

Solving
24 + 14x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(12 + x)(2 + x) = 0

Subproblem 1

Set the factor '(12 + x)' equal to zero and attempt to solve: Simplifying 12 + x = 0 Solving 12 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + x = 0 + -12 Combine like terms: 12 + -12 = 0 0 + x = 0 + -12 x = 0 + -12 Combine like terms: 0 + -12 = -12 x = -12 Simplifying x = -12

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Solution

x = {-12, -2}

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