(x+2)(x+1)=(x+4)(x+5)

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Solution for (x+2)(x+1)=(x+4)(x+5) equation:



(x+2)(x+1)=(x+4)(x+5)
We move all terms to the left:
(x+2)(x+1)-((x+4)(x+5))=0
We multiply parentheses ..
(+x^2+x+2x+2)-((x+4)(x+5))=0
We calculate terms in parentheses: -((x+4)(x+5)), so:
(x+4)(x+5)
We multiply parentheses ..
(+x^2+5x+4x+20)
We get rid of parentheses
x^2+5x+4x+20
We add all the numbers together, and all the variables
x^2+9x+20
Back to the equation:
-(x^2+9x+20)
We get rid of parentheses
x^2-x^2+x+2x-9x+2-20=0
We add all the numbers together, and all the variables
-6x-18=0
We move all terms containing x to the left, all other terms to the right
-6x=18
x=18/-6
x=-3

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