(x+2)(2x-4)=

Solution for (x+2)(2x-4)= equation:

Simplifying
(x + 2)(2x + -4) = 0

Reorder the terms:
(2 + x)(2x + -4) = 0

Reorder the terms:
(2 + x)(-4 + 2x) = 0

Multiply (2 + x) * (-4 + 2x)
(2(-4 + 2x) + x(-4 + 2x)) = 0
((-4 * 2 + 2x * 2) + x(-4 + 2x)) = 0
((-8 + 4x) + x(-4 + 2x)) = 0
(-8 + 4x + (-4 * x + 2x * x)) = 0
(-8 + 4x + (-4x + 2x2)) = 0

Combine like terms: 4x + -4x = 0
(-8 + 0 + 2x2) = 0
(-8 + 2x2) = 0

Solving
-8 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2x2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2x2 = 0 + 8
2x2 = 0 + 8

Combine like terms: 0 + 8 = 8
2x2 = 8

Divide each side by '2'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}