(x+2)(2x+2)(3x-1)=33

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Solution for (x+2)(2x+2)(3x-1)=33 equation:



(x+2)(2x+2)(3x-1)=33
We move all terms to the left:
(x+2)(2x+2)(3x-1)-(33)=0
We multiply parentheses ..
(+2x^2+2x+4x+4)(3x-1)-33=0
We move all terms containing x to the left, all other terms to the right
(+2x^2+2x+4x+4)(3x-1)=33

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