(x+2)(1/x+2)+2(x+2)=(x+2)(9/X+2)

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Solution for (x+2)(1/x+2)+2(x+2)=(x+2)(9/X+2) equation: 



(x+2)(1/x+2)+2(x+2)=(x+2)(9/x+2)

We move all terms to the left:

(x+2)(1/x+2)+2(x+2)-((x+2)(9/x+2))=0



Domain of the equation: x+2)!=0

x∈R





Domain of the equation: x+2))!=0

x∈R



We multiply parentheses

(x+2)(1/x+2)+2x-((x+2)(9/x+2))+4=0

We multiply parentheses ..

(+x^2+2x+2x+4)+2x-((x+2)(9/x+2))+4=0

We multiply all the terms by the denominator


((+x^2+2x+2x+4))*x+2))+2x*x+2))-((x+2)(9+4*x+2))=0

We add all the numbers together, and all the variables

((+x^2+2x+2x+4))*x+2))+2x*x+2))-((x+2)(4x+11))=0

We multiply parentheses ..

((+x^2+2x+2x+4))*x+2))+2x*x+2))-((+4x^2+11x+8x+22))=0

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