(x+17)(2x=19)(6x-5)=

Solution for (x+17)(2x=19)(6x-5)= equation:

(x+17)(2x=19)(6x-5)=

We move all terms to the left:

(x+17)(2x-(19)(6x-5))=0


We calculate terms in parentheses: +(x+17)(2x-19(6x-5)), so:

x+17)(2x-19(6x-5)

We multiply parentheses

x+17)(2x-114x+95

We add all the numbers together, and all the variables

-113x+17)(2x+95

Back to the equation:

+(-113x+17)(2x+95)


We multiply parentheses ..

(-226x^2-10735x+34x+1615)=0

We get rid of parentheses

-226x^2-10735x+34x+1615=0

We add all the numbers together, and all the variables

-226x^2-10701x+1615=0

a = -226; b = -10701; c = +1615;
Δ = b2-4ac
Δ = -107012-4·(-226)·1615
Δ = 115971361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{115971361}=10769$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10701)-10769}{2*-226}=\frac{-68}{-452}
=17/113
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10701)+10769}{2*-226}=\frac{21470}{-452}
=-47+1/2
$