(x+13/x+4)+1=(9/x+4)

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Solution for (x+13/x+4)+1=(9/x+4) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+13/x+1+4 = 9/x+4 // - 9/x+4

x+13/x-(9/x)-4+1+4 = 0

x+13/x-9*x^-1-4+1+4 = 0

1*x^1+4*x^-1+1*x^0 = 0

(1*x^2+1*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+1*x^1+4*x^0) = 0

x^1

x^2+x+4 = 0

x^2+x+4 = 0

DELTA = 1^2-(1*4*4)

DELTA = -15

DELTA < 0

x in { } 

x belongs to the empty set

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