(x+11)+(x+13)+(2x-14)+(3x-22)+(x-3)+41+38=1260

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Solution for (x+11)+(x+13)+(2x-14)+(3x-22)+(x-3)+41+38=1260 equation: 



(x+11)+(x+13)+(2x-14)+(3x-22)+(x-3)+41+38=1260

We move all terms to the left:

(x+11)+(x+13)+(2x-14)+(3x-22)+(x-3)+41+38-(1260)=0

We add all the numbers together, and all the variables

(x+11)+(x+13)+(2x-14)+(3x-22)+(x-3)-1181=0

We get rid of parentheses

x+x+2x+3x+x+11+13-14-22-3-1181=0

We add all the numbers together, and all the variables

8x-1196=0

We move all terms containing x to the left, all other terms to the right

8x=1196

x=1196/8

x=149+1/2

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