(x+10)+(3x+30)+(6x-20)=180

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Solution for (x+10)+(3x+30)+(6x-20)=180 equation: 



(x+10)+(3x+30)+(6x-20)=180

We move all terms to the left:

(x+10)+(3x+30)+(6x-20)-(180)=0

We get rid of parentheses

x+3x+6x+10+30-20-180=0

We add all the numbers together, and all the variables

10x-160=0

We move all terms containing x to the left, all other terms to the right

10x=160

x=160/10

x=16

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