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(x+10)(2x+5)=0
We multiply parentheses ..
(+2x^2+5x+20x+50)=0
We get rid of parentheses
2x^2+5x+20x+50=0
We add all the numbers together, and all the variables
2x^2+25x+50=0
a = 2; b = 25; c = +50;
Δ = b2-4ac
Δ = 252-4·2·50
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-15}{2*2}=\frac{-40}{4} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+15}{2*2}=\frac{-10}{4} =-2+1/2 $
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