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(x+10)(x+8)=90
We move all terms to the left:
(x+10)(x+8)-(90)=0
We multiply parentheses ..
(+x^2+8x+10x+80)-90=0
We get rid of parentheses
x^2+8x+10x+80-90=0
We add all the numbers together, and all the variables
x^2+18x-10=0
a = 1; b = 18; c = -10;
Δ = b2-4ac
Δ = 182-4·1·(-10)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{91}}{2*1}=\frac{-18-2\sqrt{91}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{91}}{2*1}=\frac{-18+2\sqrt{91}}{2} $
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