(x+1)2=12+(x-5)2

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Solution for (x+1)2=12+(x-5)2 equation: 


Simplifying
(x + 1) * 2 = 12 + (x + -5) * 2

Reorder the terms:
(1 + x) * 2 = 12 + (x + -5) * 2

Reorder the terms for easier multiplication:
2(1 + x) = 12 + (x + -5) * 2
(1 * 2 + x * 2) = 12 + (x + -5) * 2
(2 + 2x) = 12 + (x + -5) * 2

Reorder the terms:
2 + 2x = 12 + (-5 + x) * 2

Reorder the terms for easier multiplication:
2 + 2x = 12 + 2(-5 + x)
2 + 2x = 12 + (-5 * 2 + x * 2)
2 + 2x = 12 + (-10 + 2x)

Combine like terms: 12 + -10 = 2
2 + 2x = 2 + 2x

Add '-2' to each side of the equation.
2 + -2 + 2x = 2 + -2 + 2x

Combine like terms: 2 + -2 = 0
0 + 2x = 2 + -2 + 2x
2x = 2 + -2 + 2x

Combine like terms: 2 + -2 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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