(x+1)2+5(x+1)+4=0

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Solution for (x+1)2+5(x+1)+4=0 equation:


Simplifying
(x + 1) * 2 + 5(x + 1) + 4 = 0

Reorder the terms:
(1 + x) * 2 + 5(x + 1) + 4 = 0

Reorder the terms for easier multiplication:
2(1 + x) + 5(x + 1) + 4 = 0
(1 * 2 + x * 2) + 5(x + 1) + 4 = 0
(2 + 2x) + 5(x + 1) + 4 = 0

Reorder the terms:
2 + 2x + 5(1 + x) + 4 = 0
2 + 2x + (1 * 5 + x * 5) + 4 = 0
2 + 2x + (5 + 5x) + 4 = 0

Reorder the terms:
2 + 5 + 4 + 2x + 5x = 0

Combine like terms: 2 + 5 = 7
7 + 4 + 2x + 5x = 0

Combine like terms: 7 + 4 = 11
11 + 2x + 5x = 0

Combine like terms: 2x + 5x = 7x
11 + 7x = 0

Solving
11 + 7x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 7x = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 7x = 0 + -11
7x = 0 + -11

Combine like terms: 0 + -11 = -11
7x = -11

Divide each side by '7'.
x = -1.571428571

Simplifying
x = -1.571428571

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