(x+1)12=(3x-2)20

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Solution for (x+1)12=(3x-2)20 equation: 



(x+1)12=(3x-2)20

We move all terms to the left:

(x+1)12-((3x-2)20)=0

We multiply parentheses

12x-((3x-2)20)+12=0



We calculate terms in parentheses: -((3x-2)20), so:

(3x-2)20

We multiply parentheses

60x-40

Back to the equation:

-(60x-40)



We get rid of parentheses

12x-60x+40+12=0

We add all the numbers together, and all the variables

-48x+52=0

We move all terms containing x to the left, all other terms to the right

-48x=-52

x=-52/-48

x=1+1/12

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