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(x+1)/x=x/(x-3)
We move all terms to the left:
(x+1)/x-(x/(x-3))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-3))!=0We calculate fractions
x∈R
-2x^2)+(-(x*x)/(-2x^2)+((x+1)*(x-3)))/(=0
We add all the numbers together, and all the variables
-2x^2)+(-(+x*x)/(-2x^2)+((x+1)*(x-3)))/(=0
We calculate fractions
-2x^2)+(+(-(+x*x)*()/((-2x^2)*()+(-2x^2)+((x+1)*(x-3)))*()/((-2x^2)*()=0
We calculate terms in parentheses: +(-(+x*x)*()/((-2x^2)*()+(-2x^2)+((x+1)*(x-3)))*()/((-2x^2)*(), so:
-(+x*x)*()/((-2x^2)*()+(-2x^2)+((x+1)*(x-3)))*()/((-2x^2)*(
We can not solve this equation
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