(x+1)/5=(2x-2)/6

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Solution for (x+1)/5=(2x-2)/6 equation: 


x in (-oo:+oo)

(x+1)/5 = (2*x-2)/6 // - (2*x-2)/6

(x+1)/5-((2*x-2)/6) = 0

(x+1)/5+(-1*(2*x-2))/6 = 0

(6*(x+1))/(5*6)+(-1*5*(2*x-2))/(5*6) = 0

6*(x+1)-1*5*(2*x-2) = 0

16-4*x = 0

(16-4*x)/(5*6) = 0

(16-4*x)/(5*6) = 0 // * 5*6

16-4*x = 0

16-4*x = 0 // - 16

-4*x = -16 // : -4

x = -16/(-4)

x = 4

x = 4

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