(x+1)/2=(x-5)/3-2

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Solution for (x+1)/2=(x-5)/3-2 equation: 


x in (-oo:+oo)

(x+1)/2 = (x-5)/3-2 // - (x-5)/3-2

(x+1)/2-((x-5)/3)+2 = 0

(x+1)/2+(-1*(x-5))/3+2 = 0

(3*(x+1))/(2*3)+(-1*2*(x-5))/(2*3)+(3*2^2)/(2*3) = 0

3*(x+1)-1*2*(x-5)+3*2^2 = 0

x+12+13 = 0

x+25 = 0

(x+25)/(2*3) = 0

(x+25)/(2*3) = 0 // * 2*3

x+25 = 0

x+25 = 0 // - 25

x = -25

x = -25

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