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(x+1)/(x-5)=3
We move all terms to the left:
(x+1)/(x-5)-(3)=0
Domain of the equation: (x-5)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=5
x∈R
(x+1)-3*(x-5)=0
We multiply parentheses
(x+1)-3x+15=0
We get rid of parentheses
x-3x+1+15=0
We add all the numbers together, and all the variables
-2x+16=0
We move all terms containing x to the left, all other terms to the right
-2x=-16
x=-16/-2
x=+8
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