(x+1)/(x-3)-3/5=4/(x-3)

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Solution for (x+1)/(x-3)-3/5=4/(x-3) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

(x+1)/(x-3)-(3/5) = 4/(x-3) // - 4/(x-3)

(x+1)/(x-3)-(4/(x-3))-(3/5) = 0

(x+1)/(x-3)-4*(x-3)^-1-3/5 = 0

(x+1)/(x-3)-4/(x-3)-3/5 = 0

(5*(x+1))/(5*(x-3))+(-4*5)/(5*(x-3))+(-3*(x-3))/(5*(x-3)) = 0

5*(x+1)-3*(x-3)-4*5 = 0

5*x-3*x-15+9 = 0

2*x-6 = 0

(2*x-6)/(5*(x-3)) = 0

(2*x-6)/(5*(x-3)) = 0 // * 5*(x-3)

2*x-6 = 0

2*x-6 = 0 // + 6

2*x = 6 // : 2

x = 6/2

x = 3

x in { 3} 

x belongs to the empty set

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