(x+1)-3(x-1)+6=2

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Solution for (x+1)-3(x-1)+6=2 equation: 



(x+1)-3(x-1)+6=2

We move all terms to the left:

(x+1)-3(x-1)+6-(2)=0

We add all the numbers together, and all the variables

(x+1)-3(x-1)+4=0

We multiply parentheses

(x+1)-3x+3+4=0

We get rid of parentheses

x-3x+1+3+4=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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