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(x+1)-(x-1)=(x+1)+4)-(2x+2)
We move all terms to the left:
(x+1)-(x-1)-((x+1)+4)-(2x+2))=0
We get rid of parentheses
x-x-((x+1)+4)-2x+1+1-2)=0
We calculate terms in parentheses: -((x+1)+4), so:We add all the numbers together, and all the variables
(x+1)+4
We get rid of parentheses
x+1+4
We add all the numbers together, and all the variables
x+5
Back to the equation:
-(x+5)
-2x-(x+5)=0
We get rid of parentheses
-2x-x-5=0
We add all the numbers together, and all the variables
-3x-5=0
We move all terms containing x to the left, all other terms to the right
-3x=5
x=5/-3
x=-1+2/3
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