(x+1)-(1+x)=-(x+1)+(1+x)

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Solution for (x+1)-(1+x)=-(x+1)+(1+x) equation: 


Simplifying
(x + 1) + -1(1 + x) = -1(x + 1) + (1 + x)

Reorder the terms:
(1 + x) + -1(1 + x) = -1(x + 1) + (1 + x)

Remove parenthesis around (1 + x)
1 + x + -1(1 + x) = -1(x + 1) + (1 + x)
1 + x + (1 * -1 + x * -1) = -1(x + 1) + (1 + x)
1 + x + (-1 + -1x) = -1(x + 1) + (1 + x)

Reorder the terms:
1 + -1 + x + -1x = -1(x + 1) + (1 + x)

Combine like terms: 1 + -1 = 0
0 + x + -1x = -1(x + 1) + (1 + x)
x + -1x = -1(x + 1) + (1 + x)

Combine like terms: x + -1x = 0
0 = -1(x + 1) + (1 + x)

Reorder the terms:
0 = -1(1 + x) + (1 + x)
0 = (1 * -1 + x * -1) + (1 + x)
0 = (-1 + -1x) + (1 + x)

Remove parenthesis around (1 + x)
0 = -1 + -1x + 1 + x

Reorder the terms:
0 = -1 + 1 + -1x + x

Combine like terms: -1 + 1 = 0
0 = 0 + -1x + x
0 = -1x + x

Combine like terms: -1x + x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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