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(x+1)+(x+5)=(x+2)+(x+3)
We move all terms to the left:
(x+1)+(x+5)-((x+2)+(x+3))=0
We get rid of parentheses
x+x-((x+2)+(x+3))+1+5=0
We calculate terms in parentheses: -((x+2)+(x+3)), so:We add all the numbers together, and all the variables
(x+2)+(x+3)
We get rid of parentheses
x+x+2+3
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
2x-(2x+5)+6=0
We get rid of parentheses
2x-2x-5+6=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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