(x+1)+(x+2)+(x+3)+(x+4)=160

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Solution for (x+1)+(x+2)+(x+3)+(x+4)=160 equation: 



(x+1)+(x+2)+(x+3)+(x+4)=160

We move all terms to the left:

(x+1)+(x+2)+(x+3)+(x+4)-(160)=0

We get rid of parentheses

x+x+x+x+1+2+3+4-160=0

We add all the numbers together, and all the variables

4x-150=0

We move all terms containing x to the left, all other terms to the right

4x=150

x=150/4

x=37+1/2

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